Solve |2|k+2k

$$| 2 | k + 2 k$$

Evaluate

$$4k$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 2 is 2.

$$2k+2k$$

Combine 2k and 2k to get 4k.

$$4k$$

Differentiate w.r.t. k

$$4$$

Steps Using Definition of a Derivative

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 2 is 2.

$$\frac{\mathrm{d}}{\mathrm{d}k}(2k+2k)$$

Combine 2k and 2k to get 4k.

$$\frac{\mathrm{d}}{\mathrm{d}k}(4k)$$

The derivative of ax^{n} is nax^{n-1}.

$$4k^{1-1}$$

Subtract 1 from 1.

$$4k^{0}$$

For any term t except 0, t^{0}=1.

$$4\times 1$$

For any term t, t\times 1=t and 1t=t.

$$4$$