Solve |-8|div|-9|-5(-8)+3^2

$$| - 8 | \div | - 9 | - 5 ( - 8 ) + 3 ^ { 2 }$$

Evaluate

$$\frac{449}{9}\approx 49.888888889$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -8 is 8.

$$\frac{8}{|-9|}-5\left(-8\right)+3^{2}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -9 is 9.

$$\frac{8}{9}-5\left(-8\right)+3^{2}$$

Multiply 5 and -8 to get -40.

$$\frac{8}{9}-\left(-40\right)+3^{2}$$

The opposite of -40 is 40.

$$\frac{8}{9}+40+3^{2}$$

Convert 40 to fraction \frac{360}{9}.

$$\frac{8}{9}+\frac{360}{9}+3^{2}$$

Since \frac{8}{9} and \frac{360}{9} have the same denominator, add them by adding their numerators.

$$\frac{8+360}{9}+3^{2}$$

Add 8 and 360 to get 368.

$$\frac{368}{9}+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{368}{9}+9$$

Convert 9 to fraction \frac{81}{9}.

$$\frac{368}{9}+\frac{81}{9}$$

Since \frac{368}{9} and \frac{81}{9} have the same denominator, add them by adding their numerators.

$$\frac{368+81}{9}$$

Add 368 and 81 to get 449.

$$\frac{449}{9}$$

Factor

$$\frac{449}{3 ^ {2}} = 49\frac{8}{9} = 49.888888888888886$$