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5-\left(\sqrt{2}-1\right)^{0}+\left(-\frac{1}{3}\right)^{-2}+\sqrt[3]{-27}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -5 is 5.
5-1+\left(-\frac{1}{3}\right)^{-2}+\sqrt[3]{-27}
Calculate \sqrt{2}-1 to the power of 0 and get 1.
4+\left(-\frac{1}{3}\right)^{-2}+\sqrt[3]{-27}
Subtract 1 from 5 to get 4.
4+9+\sqrt[3]{-27}
Calculate -\frac{1}{3} to the power of -2 and get 9.
13+\sqrt[3]{-27}
Add 4 and 9 to get 13.
13-3
Calculate \sqrt[3]{-27} and get -3.
10
Subtract 3 from 13 to get 10.