Solve |-3|+(pi-2017)^0-2sin30^circ+(1/3)^-1

$$| - 3 | + ( \pi - 2017 ) ^ { 0 } - 2 \sin 30 ^ { \circ } + ( \frac { 1 } { 3 } ) ^ { - 1 }$$

Evaluate

$$6$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$3+\left(\pi -2017\right)^{0}-2\sin(30)+\left(\frac{1}{3}\right)^{-1}$$

Calculate \pi -2017 to the power of 0 and get 1.

$$3+1-2\sin(30)+\left(\frac{1}{3}\right)^{-1}$$

Add 3 and 1 to get 4.

$$4-2\sin(30)+\left(\frac{1}{3}\right)^{-1}$$

Get the value of \sin(30) from trigonometric values table.

$$4-2\times \frac{1}{2}+\left(\frac{1}{3}\right)^{-1}$$

Multiply 2 and \frac{1}{2} to get 1.

$$4-1+\left(\frac{1}{3}\right)^{-1}$$

Subtract 1 from 4 to get 3.

$$3+\left(\frac{1}{3}\right)^{-1}$$

Calculate \frac{1}{3} to the power of -1 and get 3.

$$3+3$$

Add 3 and 3 to get 6.

$$6$$