Solve |-3|+sqrt[3]{-27}-sqrt{(-4)^2}

$$| - 3 | + \sqrt[ 3 ] { - 27 } - \sqrt { ( - 4 ) ^ { 2 } }$$

Evaluate

$$-4$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$3+\sqrt[3]{-27}-\sqrt{\left(-4\right)^{2}}$$

Calculate \sqrt[3]{-27} and get -3.

$$3-3-\sqrt{\left(-4\right)^{2}}$$

Subtract 3 from 3 to get 0.

$$-\sqrt{\left(-4\right)^{2}}$$

Calculate -4 to the power of 2 and get 16.

$$-\sqrt{16}$$

Calculate the square root of 16 and get 4.

$$-4$$

Factor

$$-4$$