Solve |-2|+(pi-3)^0-frac{1}(3)^-2+(-1)^2016

$$| - 2 | + ( \pi - 3 ) ^ { 0 } - \frac { 1 } { ( 3 ) } ^ { - 2 } + ( - 1 ) ^ { 2016 }$$

Evaluate

$$-5$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -2 is 2.

$$2+\left(\pi -3\right)^{0}-\left(\frac{1}{3}\right)^{-2}+\left(-1\right)^{2016}$$

Calculate \pi -3 to the power of 0 and get 1.

$$2+1-\left(\frac{1}{3}\right)^{-2}+\left(-1\right)^{2016}$$

Add 2 and 1 to get 3.

$$3-\left(\frac{1}{3}\right)^{-2}+\left(-1\right)^{2016}$$

Calculate \frac{1}{3} to the power of -2 and get 9.

$$3-9+\left(-1\right)^{2016}$$

Subtract 9 from 3 to get -6.

$$-6+\left(-1\right)^{2016}$$

Calculate -1 to the power of 2016 and get 1.

$$-6+1$$

Add -6 and 1 to get -5.

$$-5$$

Factor

$$-5$$