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2+\left(\pi -3\right)^{0}+\left(-1\right)^{2016}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -2 is 2.
2+1+\left(-1\right)^{2016}
Calculate \pi -3 to the power of 0 and get 1.
3+\left(-1\right)^{2016}
Add 2 and 1 to get 3.
3+1
Calculate -1 to the power of 2016 and get 1.
4
Add 3 and 1 to get 4.