Solve |-15|:|5|+|-24|+|3|-|-18|=

$$| - 15 | : | 5 | + | - 24 | + | 3 | - | - 18 | =$$

Evaluate

$$12$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -15 is 15.

$$\frac{15}{|5|}+|-24|+|3|-|-18|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 5 is 5.

$$\frac{15}{5}+|-24|+|3|-|-18|$$

Divide 15 by 5 to get 3.

$$3+|-24|+|3|-|-18|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -24 is 24.

$$3+24+|3|-|-18|$$

Add 3 and 24 to get 27.

$$27+|3|-|-18|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 3 is 3.

$$27+3-|-18|$$

Add 27 and 3 to get 30.

$$30-|-18|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -18 is 18.

$$30-18$$

Subtract 18 from 30 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$