Solve |(-4)+(-5)*(-5+7-4)|:(-4+2)-(-6)=

$$| ( - 4 ) + ( - 5 ) \cdot ( - 5 + 7 - 4 ) | : ( - 4 + 2 ) - ( - 6 ) =$$

Evaluate

$$3$$

Solution Steps

Add -5 and 7 to get 2.

$$\frac{|-4-5\left(2-4\right)|}{-4+2}-\left(-6\right)$$

Subtract 4 from 2 to get -2.

$$\frac{|-4-5\left(-2\right)|}{-4+2}-\left(-6\right)$$

Multiply -5 and -2 to get 10.

$$\frac{|-4+10|}{-4+2}-\left(-6\right)$$

Add -4 and 10 to get 6.

$$\frac{|6|}{-4+2}-\left(-6\right)$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 6 is 6.

$$\frac{6}{-4+2}-\left(-6\right)$$

Add -4 and 2 to get -2.

$$\frac{6}{-2}-\left(-6\right)$$

Divide 6 by -2 to get -3.

$$-3-\left(-6\right)$$

The opposite of -6 is 6.

$$-3+6$$

Add -3 and 6 to get 3.

$$3$$

Factor

$$3$$