Solve ||5/6-9/1|-|-||3=

$$| | \frac { 5 } { 6 } - \frac { 9 } { 1 } | - | - | |3 =$$

Evaluate

$$\frac{31}{6}\approx 5.166666667$$

Solution Steps

Anything divided by one gives itself.

$$||\frac{5}{6}-9|-|-||3||||$$

Convert 9 to fraction \frac{54}{6}.

$$||\frac{5}{6}-\frac{54}{6}|-|-||3||||$$

Since \frac{5}{6} and \frac{54}{6} have the same denominator, subtract them by subtracting their numerators.

$$||\frac{5-54}{6}|-|-||3||||$$

Subtract 54 from 5 to get -49.

$$||-\frac{49}{6}|-|-||3||||$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -\frac{49}{6} is \frac{49}{6}.

$$|\frac{49}{6}-|-||3||||$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 3 is 3.

$$|\frac{49}{6}-|-|3|||$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 3 is 3.

$$|\frac{49}{6}-|-3||$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$|\frac{49}{6}-3|$$

Convert 3 to fraction \frac{18}{6}.

$$|\frac{49}{6}-\frac{18}{6}|$$

Since \frac{49}{6} and \frac{18}{6} have the same denominator, subtract them by subtracting their numerators.

$$|\frac{49-18}{6}|$$

Subtract 18 from 49 to get 31.

$$|\frac{31}{6}|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{31}{6} is \frac{31}{6}.

$$\frac{31}{6}$$

Factor

$$\frac{31}{2 \cdot 3} = 5\frac{1}{6} = 5.166666666666667$$