Solve for x
x=-16
x=64
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|\frac{1}{8}x-3|=5
Divide each term of x-24 by 8 to get \frac{1}{8}x-3.
\frac{1}{8}x-3=5 \frac{1}{8}x-3=-5
Use the definition of absolute value.
\frac{1}{8}x=8 \frac{1}{8}x=-2
Add 3 to both sides of the equation.
x=64 x=-16
Multiply both sides by 8.
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