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\frac{5}{6}-\frac{1}{2}+\frac{17}{24}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{5}{6} is \frac{5}{6}.
\frac{5}{6}-\frac{3}{6}+\frac{17}{24}
Least common multiple of 6 and 2 is 6. Convert \frac{5}{6} and \frac{1}{2} to fractions with denominator 6.
\frac{5-3}{6}+\frac{17}{24}
Since \frac{5}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.
\frac{2}{6}+\frac{17}{24}
Subtract 3 from 5 to get 2.
\frac{1}{3}+\frac{17}{24}
Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.
\frac{8}{24}+\frac{17}{24}
Least common multiple of 3 and 24 is 24. Convert \frac{1}{3} and \frac{17}{24} to fractions with denominator 24.
\frac{8+17}{24}
Since \frac{8}{24} and \frac{17}{24} have the same denominator, add them by adding their numerators.
\frac{25}{24}
Add 8 and 17 to get 25.