Solve |3/4-(1/2)|+1=

$$| \frac { 3 } { 4 } - ( \frac { 1 } { 2 } ) | + 1 =$$

Evaluate

$$\frac{5}{4}=1.25$$

Solution Steps

Least common multiple of 4 and 2 is 4. Convert \frac{3}{4} and \frac{1}{2} to fractions with denominator 4.

$$|\frac{3}{4}-\frac{2}{4}|+1$$

Since \frac{3}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.

$$|\frac{3-2}{4}|+1$$

Subtract 2 from 3 to get 1.

$$|\frac{1}{4}|+1$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{1}{4} is \frac{1}{4}.

$$\frac{1}{4}+1$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{1}{4}+\frac{4}{4}$$

Since \frac{1}{4} and \frac{4}{4} have the same denominator, add them by adding their numerators.

$$\frac{1+4}{4}$$

Add 1 and 4 to get 5.

$$\frac{5}{4}$$

Factor

$$\frac{5}{2 ^ {2}} = 1\frac{1}{4} = 1.25$$