Solve |3/4*(-5/6)|+(-3/5)

$$| \frac { 3 } { 4 } \cdot ( - \frac { 5 } { 6 } ) | + ( - \frac { 3 } { 5 } )$$

Evaluate

$$\frac{1}{40}=0.025$$

Solution Steps

Multiply \frac{3}{4} times -\frac{5}{6} by multiplying numerator times numerator and denominator times denominator.

$$|\frac{3\left(-5\right)}{4\times 6}|-\frac{3}{5}$$

Do the multiplications in the fraction \frac{3\left(-5\right)}{4\times 6}.

$$|\frac{-15}{24}|-\frac{3}{5}$$

Reduce the fraction \frac{-15}{24} to lowest terms by extracting and canceling out 3.

$$|-\frac{5}{8}|-\frac{3}{5}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -\frac{5}{8} is \frac{5}{8}.

$$\frac{5}{8}-\frac{3}{5}$$

Least common multiple of 8 and 5 is 40. Convert \frac{5}{8} and \frac{3}{5} to fractions with denominator 40.

$$\frac{25}{40}-\frac{24}{40}$$

Since \frac{25}{40} and \frac{24}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-24}{40}$$

Subtract 24 from 25 to get 1.

$$\frac{1}{40}$$

Factor

$$\frac{1}{2 ^ {3} \cdot 5} = 0.025$$