Solve |1/6*(3/4+1/5)

$$| \frac { 1 } { 6 } \times ( \frac { 3 } { 4 } + \frac { 1 } { 5 } )$$

Evaluate

$$\frac{19}{120}\approx 0.158333333$$

Solution Steps

Least common multiple of 4 and 5 is 20. Convert \frac{3}{4} and \frac{1}{5} to fractions with denominator 20.

$$|\frac{1}{6}\left(\frac{15}{20}+\frac{4}{20}\right)|$$

Since \frac{15}{20} and \frac{4}{20} have the same denominator, add them by adding their numerators.

$$|\frac{1}{6}\times \frac{15+4}{20}|$$

Add 15 and 4 to get 19.

$$|\frac{1}{6}\times \frac{19}{20}|$$

Multiply \frac{1}{6} times \frac{19}{20} by multiplying numerator times numerator and denominator times denominator.

$$|\frac{1\times 19}{6\times 20}|$$

Do the multiplications in the fraction \frac{1\times 19}{6\times 20}.

$$|\frac{19}{120}|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{19}{120} is \frac{19}{120}.

$$\frac{19}{120}$$

Factor

$$\frac{19}{2 ^ {3} \cdot 3 \cdot 5} = 0.15833333333333333$$