Solve {(e)^6lceil4^circlfloor5rfloorrceil}

$${(e)^{ 6 \lceil 4 ^ { \circ } \lfloor 5 \rfloor \rceil }}$$

Evaluate

$$e^{120}\approx 1.304180878 \cdot 10^{52}$$

Solution Steps

The floor of a real number a is the largest integer number less than or equal to a. The floor of 5 is 5.

$$e^{6\lceil 4\times 5\rceil }$$

Multiply 4 and 5 to get 20.

$$e^{6\lceil 20\rceil }$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of 20 is 20.

$$e^{6\times 20}$$

Multiply 6 and 20 to get 120.

$$e^{120}$$