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z\left(z-3\right)=0
Factor out z.
z=0 z=3
To find equation solutions, solve z=0 and z-3=0.
z^{2}-3z=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
z=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -3 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
z=\frac{-\left(-3\right)±3}{2}
Take the square root of \left(-3\right)^{2}.
z=\frac{3±3}{2}
The opposite of -3 is 3.
z=\frac{6}{2}
Now solve the equation z=\frac{3±3}{2} when ± is plus. Add 3 to 3.
z=3
Divide 6 by 2.
z=\frac{0}{2}
Now solve the equation z=\frac{3±3}{2} when ± is minus. Subtract 3 from 3.
z=0
Divide 0 by 2.
z=3 z=0
The equation is now solved.
z^{2}-3z=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
z^{2}-3z+\left(-\frac{3}{2}\right)^{2}=\left(-\frac{3}{2}\right)^{2}
Divide -3, the coefficient of the x term, by 2 to get -\frac{3}{2}. Then add the square of -\frac{3}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
z^{2}-3z+\frac{9}{4}=\frac{9}{4}
Square -\frac{3}{2} by squaring both the numerator and the denominator of the fraction.
\left(z-\frac{3}{2}\right)^{2}=\frac{9}{4}
Factor z^{2}-3z+\frac{9}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(z-\frac{3}{2}\right)^{2}}=\sqrt{\frac{9}{4}}
Take the square root of both sides of the equation.
z-\frac{3}{2}=\frac{3}{2} z-\frac{3}{2}=-\frac{3}{2}
Simplify.
z=3 z=0
Add \frac{3}{2} to both sides of the equation.