Solve z^2+10z+16=(z+8)(z

$${ z }^{ 2 } +10z+16=(z+8)(z$$

Solve for z

$$z=-8$$

Steps for Solving Linear Equation

Use the distributive property to multiply z+8 by z.

$$z^{2}+10z+16=z^{2}+8z$$

Subtract z^{2} from both sides.

$$z^{2}+10z+16-z^{2}=8z$$

Combine z^{2} and -z^{2} to get 0.

$$10z+16=8z$$

Subtract 8z from both sides.

$$10z+16-8z=0$$

Combine 10z and -8z to get 2z.

$$2z+16=0$$

Subtract 16 from both sides. Anything subtracted from zero gives its negation.

$$2z=-16$$

Divide both sides by 2.

$$z=\frac{-16}{2}$$

Divide -16 by 2 to get -8.

$$z=-8$$