Solve y^2-8x-6y+25=0

$${ y }^{ 2 } -8x-6y+25=0$$

Solve for x

$$x=\frac{y^{2}-6y+25}{8}$$

Steps for Solving Linear Equation

Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-8x-6y+25=-y^{2}$$

Add 6y to both sides.

$$-8x+25=-y^{2}+6y$$

Subtract 25 from both sides.

$$-8x=-y^{2}+6y-25$$

Divide both sides by -8.

$$\frac{-8x}{-8}=\frac{-y^{2}+6y-25}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$x=\frac{-y^{2}+6y-25}{-8}$$

Divide -y^{2}+6y-25 by -8.

$$x=\frac{y^{2}}{8}-\frac{3y}{4}+\frac{25}{8}$$

Solve for y (complex solution)

$$y=2\sqrt{2\left(x-2\right)}+3$$

$$y=-2\sqrt{2\left(x-2\right)}+3$$

Solve for y

$$y=2\sqrt{2\left(x-2\right)}+3$$

$$y=-2\sqrt{2\left(x-2\right)}+3\text{, }x\geq 2$$