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x^{6}\left(x^{3}+x^{2}+x+1\right)
Factor out x^{6}.
x^{2}\left(x+1\right)+x+1
Consider x^{3}+x^{2}+x+1. Do the grouping x^{3}+x^{2}+x+1=\left(x^{3}+x^{2}\right)+\left(x+1\right), and factor out x^{2} in x^{3}+x^{2}.
\left(x+1\right)\left(x^{2}+1\right)
Factor out common term x+1 by using distributive property.
x^{6}\left(x+1\right)\left(x^{2}+1\right)
Rewrite the complete factored expression. Polynomial x^{2}+1 is not factored since it does not have any rational roots.