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\left(y^{2}x^{3}+1\right)\left(y^{4}x^{6}-y^{2}x^{3}+1\right)
Rewrite x^{9}y^{6}+1 as \left(y^{2}x^{3}\right)^{3}+1^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).