Solve for x
x=1
x=2
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t^{2}-9t+8=0
Substitute t for x^{3}.
t=\frac{-\left(-9\right)±\sqrt{\left(-9\right)^{2}-4\times 1\times 8}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -9 for b, and 8 for c in the quadratic formula.
t=\frac{9±7}{2}
Do the calculations.
t=8 t=1
Solve the equation t=\frac{9±7}{2} when ± is plus and when ± is minus.
x=2 x=1
Since x=t^{3}, the solutions are obtained by evaluating x=\sqrt[3]{t} for each t.
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