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\left(x^{3}y^{2}-z^{4}\right)\left(x^{3}y^{2}+z^{4}\right)
Rewrite x^{6}y^{4}-z^{8} as \left(x^{3}y^{2}\right)^{2}-\left(z^{4}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(y^{2}x^{3}-z^{4}\right)\left(y^{2}x^{3}+z^{4}\right)
Reorder the terms.