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\frac{6x^{4}+20x^{3}+9x^{2}-5x}{6}
Factor out \frac{1}{6}.
x\left(6x^{3}+20x^{2}+9x-5\right)
Consider 6x^{4}+20x^{3}+9x^{2}-5x. Factor out x.
\left(x+1\right)\left(6x^{2}+14x-5\right)
Consider 6x^{3}+20x^{2}+9x-5. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -5 and q divides the leading coefficient 6. One such root is -1. Factor the polynomial by dividing it by x+1.
\frac{x\left(x+1\right)\left(6x^{2}+14x-5\right)}{6}
Rewrite the complete factored expression. Polynomial 6x^{2}+14x-5 is not factored since it does not have any rational roots.