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x^{3}-8
Multiply and combine like terms.
\left(x-2\right)\left(x^{2}+2x+4\right)
Rewrite x^{3}-8 as x^{3}-2^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial x^{2}+2x+4 is not factored since it does not have any rational roots.
x^{3}-8
Calculate 2 to the power of 3 and get 8.