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x^{3}+729
Multiply and combine like terms.
\left(x+9\right)\left(x^{2}-9x+81\right)
Rewrite x^{3}+729 as x^{3}+9^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right). Polynomial x^{2}-9x+81 is not factored since it does not have any rational roots.
x^{3}+729
Calculate 9 to the power of 3 and get 729.