Solve x^281=50

$${ x }^{ 2 } 81 = 50$$

Solve for x

$$x=\frac{5\sqrt{2}}{9}\approx 0.785674201$$

$$x=-\frac{5\sqrt{2}}{9}\approx -0.785674201$$

Steps by Finding Square Root

Divide both sides by 81.

$$x^{2}=\frac{50}{81}$$

Take the square root of both sides of the equation.

$$x=\frac{5\sqrt{2}}{9} x=-\frac{5\sqrt{2}}{9}$$

Steps Using the Quadratic Formula

Divide both sides by 81.

$$x^{2}=\frac{50}{81}$$

Subtract \frac{50}{81} from both sides.

$$x^{2}-\frac{50}{81}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{50}{81} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{50}{81}\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{50}{81}\right)}}{2}$$

Multiply -4 times -\frac{50}{81}.

$$x=\frac{0±\sqrt{\frac{200}{81}}}{2}$$

Take the square root of \frac{200}{81}.

$$x=\frac{0±\frac{10\sqrt{2}}{9}}{2}$$

Now solve the equation x=\frac{0±\frac{10\sqrt{2}}{9}}{2} when ± is plus.

$$x=\frac{5\sqrt{2}}{9}$$

Now solve the equation x=\frac{0±\frac{10\sqrt{2}}{9}}{2} when ± is minus.

$$x=-\frac{5\sqrt{2}}{9}$$

The equation is now solved.

$$x=\frac{5\sqrt{2}}{9} x=-\frac{5\sqrt{2}}{9}$$