Solve x^2-8x+5

$${ x }^{ 2 } -8x+5$$

Factor

$$\left(x-\left(4-\sqrt{11}\right)\right)\left(x-\left(\sqrt{11}+4\right)\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$x^{2}-8x+5=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\times 5}}{2}$$

Square -8.

$$x=\frac{-\left(-8\right)±\sqrt{64-4\times 5}}{2}$$

Multiply -4 times 5.

$$x=\frac{-\left(-8\right)±\sqrt{64-20}}{2}$$

Add 64 to -20.

$$x=\frac{-\left(-8\right)±\sqrt{44}}{2}$$

Take the square root of 44.

$$x=\frac{-\left(-8\right)±2\sqrt{11}}{2}$$

The opposite of -8 is 8.

$$x=\frac{8±2\sqrt{11}}{2}$$

Now solve the equation x=\frac{8±2\sqrt{11}}{2} when ± is plus. Add 8 to 2\sqrt{11}.

$$x=\frac{2\sqrt{11}+8}{2}$$

Divide 8+2\sqrt{11} by 2.

$$x=\sqrt{11}+4$$

Now solve the equation x=\frac{8±2\sqrt{11}}{2} when ± is minus. Subtract 2\sqrt{11} from 8.

$$x=\frac{8-2\sqrt{11}}{2}$$

Divide 8-2\sqrt{11} by 2.

$$x=4-\sqrt{11}$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 4+\sqrt{11} for x_{1} and 4-\sqrt{11} for x_{2}.

$$x^{2}-8x+5=\left(x-\left(\sqrt{11}+4\right)\right)\left(x-\left(4-\sqrt{11}\right)\right)$$

Evaluate

$$x^{2}-8x+5$$