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x^{2}=4+6
Add 6 to both sides.
x^{2}=10
Add 4 and 6 to get 10.
x=\sqrt{10} x=-\sqrt{10}
Take the square root of both sides of the equation.
x^{2}-6-4=0
Subtract 4 from both sides.
x^{2}-10=0
Subtract 4 from -6 to get -10.
x=\frac{0±\sqrt{0^{2}-4\left(-10\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-10\right)}}{2}
Square 0.
x=\frac{0±\sqrt{40}}{2}
Multiply -4 times -10.
x=\frac{0±2\sqrt{10}}{2}
Take the square root of 40.
x=\sqrt{10}
Now solve the equation x=\frac{0±2\sqrt{10}}{2} when ± is plus.
x=-\sqrt{10}
Now solve the equation x=\frac{0±2\sqrt{10}}{2} when ± is minus.
x=\sqrt{10} x=-\sqrt{10}
The equation is now solved.