Solve for x
x=8
x=42
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a+b=-50 ab=336
To solve the equation, factor x^{2}-50x+336 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
-1,-336 -2,-168 -3,-112 -4,-84 -6,-56 -7,-48 -8,-42 -12,-28 -14,-24 -16,-21
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 336.
-1-336=-337 -2-168=-170 -3-112=-115 -4-84=-88 -6-56=-62 -7-48=-55 -8-42=-50 -12-28=-40 -14-24=-38 -16-21=-37
Calculate the sum for each pair.
a=-42 b=-8
The solution is the pair that gives sum -50.
\left(x-42\right)\left(x-8\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=42 x=8
To find equation solutions, solve x-42=0 and x-8=0.
a+b=-50 ab=1\times 336=336
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx+336. To find a and b, set up a system to be solved.
-1,-336 -2,-168 -3,-112 -4,-84 -6,-56 -7,-48 -8,-42 -12,-28 -14,-24 -16,-21
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 336.
-1-336=-337 -2-168=-170 -3-112=-115 -4-84=-88 -6-56=-62 -7-48=-55 -8-42=-50 -12-28=-40 -14-24=-38 -16-21=-37
Calculate the sum for each pair.
a=-42 b=-8
The solution is the pair that gives sum -50.
\left(x^{2}-42x\right)+\left(-8x+336\right)
Rewrite x^{2}-50x+336 as \left(x^{2}-42x\right)+\left(-8x+336\right).
x\left(x-42\right)-8\left(x-42\right)
Factor out x in the first and -8 in the second group.
\left(x-42\right)\left(x-8\right)
Factor out common term x-42 by using distributive property.
x=42 x=8
To find equation solutions, solve x-42=0 and x-8=0.
x^{2}-50x+336=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-50\right)±\sqrt{\left(-50\right)^{2}-4\times 336}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -50 for b, and 336 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-50\right)±\sqrt{2500-4\times 336}}{2}
Square -50.
x=\frac{-\left(-50\right)±\sqrt{2500-1344}}{2}
Multiply -4 times 336.
x=\frac{-\left(-50\right)±\sqrt{1156}}{2}
Add 2500 to -1344.
x=\frac{-\left(-50\right)±34}{2}
Take the square root of 1156.
x=\frac{50±34}{2}
The opposite of -50 is 50.
x=\frac{84}{2}
Now solve the equation x=\frac{50±34}{2} when ± is plus. Add 50 to 34.
x=42
Divide 84 by 2.
x=\frac{16}{2}
Now solve the equation x=\frac{50±34}{2} when ± is minus. Subtract 34 from 50.
x=8
Divide 16 by 2.
x=42 x=8
The equation is now solved.
x^{2}-50x+336=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-50x+336-336=-336
Subtract 336 from both sides of the equation.
x^{2}-50x=-336
Subtracting 336 from itself leaves 0.
x^{2}-50x+\left(-25\right)^{2}=-336+\left(-25\right)^{2}
Divide -50, the coefficient of the x term, by 2 to get -25. Then add the square of -25 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-50x+625=-336+625
Square -25.
x^{2}-50x+625=289
Add -336 to 625.
\left(x-25\right)^{2}=289
Factor x^{2}-50x+625. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-25\right)^{2}}=\sqrt{289}
Take the square root of both sides of the equation.
x-25=17 x-25=-17
Simplify.
x=42 x=8
Add 25 to both sides of the equation.
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