Solve x^2-4x+4+x^2-4-4x^2-4x

$${ x }^{ 2 } -4x+4+ { x }^{ 2 } -4-4 { x }^{ 2 } -4x$$

Evaluate

$$-2x\left(x+4\right)$$

Solution Steps

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}-4x+4-4-4x^{2}-4x$$

Subtract 4 from 4 to get 0.

$$2x^{2}-4x-4x^{2}-4x$$

Combine -4x and -4x to get -8x.

$$2x^{2}-8x-4x^{2}$$

Combine 2x^{2} and -4x^{2} to get -2x^{2}.

$$-2x^{2}-8x$$

Factor

$$-2x\left(x+4\right)$$

Solution Steps

Multiply and combine like terms.

$$-2x^{2}-8x$$

Factor out 2.

$$2\left(-x^{2}-4x\right)$$

Consider -x^{2}-4x. Factor out x.

$$x\left(-x-4\right)$$

Rewrite the complete factored expression.

$$2x\left(-x-4\right)$$