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x\left(x-49\right)=0
Factor out x.
x=0 x=49
To find equation solutions, solve x=0 and x-49=0.
x^{2}-49x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-49\right)±\sqrt{\left(-49\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -49 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-49\right)±49}{2}
Take the square root of \left(-49\right)^{2}.
x=\frac{49±49}{2}
The opposite of -49 is 49.
x=\frac{98}{2}
Now solve the equation x=\frac{49±49}{2} when ± is plus. Add 49 to 49.
x=49
Divide 98 by 2.
x=\frac{0}{2}
Now solve the equation x=\frac{49±49}{2} when ± is minus. Subtract 49 from 49.
x=0
Divide 0 by 2.
x=49 x=0
The equation is now solved.
x^{2}-49x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-49x+\left(-\frac{49}{2}\right)^{2}=\left(-\frac{49}{2}\right)^{2}
Divide -49, the coefficient of the x term, by 2 to get -\frac{49}{2}. Then add the square of -\frac{49}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-49x+\frac{2401}{4}=\frac{2401}{4}
Square -\frac{49}{2} by squaring both the numerator and the denominator of the fraction.
\left(x-\frac{49}{2}\right)^{2}=\frac{2401}{4}
Factor x^{2}-49x+\frac{2401}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{49}{2}\right)^{2}}=\sqrt{\frac{2401}{4}}
Take the square root of both sides of the equation.
x-\frac{49}{2}=\frac{49}{2} x-\frac{49}{2}=-\frac{49}{2}
Simplify.
x=49 x=0
Add \frac{49}{2} to both sides of the equation.