Solve x^2-18x+45=x^2+18x+81

$${ x }^{ 2 } -18x+45= { x }^{ 2 } +18x+81$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$x^{2}-18x+45-x^{2}=18x+81$$

Combine x^{2} and -x^{2} to get 0.

$$-18x+45=18x+81$$

Subtract 18x from both sides.

$$-18x+45-18x=81$$

Combine -18x and -18x to get -36x.

$$-36x+45=81$$

Subtract 45 from both sides.

$$-36x=81-45$$

Subtract 45 from 81 to get 36.

$$-36x=36$$

Divide both sides by -36.

$$x=\frac{36}{-36}$$

Divide 36 by -36 to get -1.

$$x=-1$$