Solve x^2-16+x^2-4+sqrt{6^2}

$${ x }^{ 2 } -16+ { x }^{ 2 } -4+ \sqrt{ { 6 }^{ 2 } }$$

Evaluate

$$2\left(x^{2}-7\right)$$

Solution Steps

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}-16-4+\sqrt{6^{2}}$$

Subtract 4 from -16 to get -20.

$$2x^{2}-20+\sqrt{6^{2}}$$

Calculate 6 to the power of 2 and get 36.

$$2x^{2}-20+\sqrt{36}$$

Calculate the square root of 36 and get 6.

$$2x^{2}-20+6$$

Add -20 and 6 to get -14.

$$2x^{2}-14$$

Factor

$$2\left(x^{2}-7\right)$$

Solution Steps

Combine x^{2} and x^{2} to get 2x^{2}.

$$factor(2x^{2}-16-4+\sqrt{6^{2}})$$

Subtract 4 from -16 to get -20.

$$factor(2x^{2}-20+\sqrt{6^{2}})$$

Calculate 6 to the power of 2 and get 36.

$$factor(2x^{2}-20+\sqrt{36})$$

Calculate the square root of 36 and get 6.

$$factor(2x^{2}-20+6)$$

Add -20 and 6 to get -14.

$$factor(2x^{2}-14)$$

Factor out 2. Polynomial x^{2}-7 is not factored since it does not have any rational roots.

$$2\left(x^{2}-7\right)$$