Solve x^2-15x+26

$${ x }^{ 2 } -15x+26$$

Factor

$$\left(x-13\right)\left(x-2\right)$$

Solution Steps

Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+26. To find a and b, set up a system to be solved.

$$a+b=-15 ab=1\times 26=26$$

Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 26.

$$-1,-26 -2,-13$$

Calculate the sum for each pair.

$$-1-26=-27 -2-13=-15$$

The solution is the pair that gives sum -15.

$$a=-13 b=-2$$

Rewrite x^{2}-15x+26 as \left(x^{2}-13x\right)+\left(-2x+26\right).

$$\left(x^{2}-13x\right)+\left(-2x+26\right)$$

Factor out x in the first and -2 in the second group.

$$x\left(x-13\right)-2\left(x-13\right)$$

Factor out common term x-13 by using distributive property.

$$\left(x-13\right)\left(x-2\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$x^{2}-15x+26=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-\left(-15\right)±\sqrt{\left(-15\right)^{2}-4\times 26}}{2}$$

Square -15.

$$x=\frac{-\left(-15\right)±\sqrt{225-4\times 26}}{2}$$

Multiply -4 times 26.

$$x=\frac{-\left(-15\right)±\sqrt{225-104}}{2}$$

Add 225 to -104.

$$x=\frac{-\left(-15\right)±\sqrt{121}}{2}$$

Take the square root of 121.

$$x=\frac{-\left(-15\right)±11}{2}$$

The opposite of -15 is 15.

$$x=\frac{15±11}{2}$$

Now solve the equation x=\frac{15±11}{2} when ± is plus. Add 15 to 11.

$$x=\frac{26}{2}$$

Divide 26 by 2.

$$x=13$$

Now solve the equation x=\frac{15±11}{2} when ± is minus. Subtract 11 from 15.

$$x=\frac{4}{2}$$

Divide 4 by 2.

$$x=2$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 13 for x_{1} and 2 for x_{2}.

$$x^{2}-15x+26=\left(x-13\right)\left(x-2\right)$$

Evaluate

$$\left(x-13\right)\left(x-2\right)$$