Solve x^2-12x-220=0

$${ x }^{ 2 } -12x-220=0$$

Solve for x

$$x=-10$$

$$x=22$$

Steps Using Factoring

To solve the equation, factor x^{2}-12x-220 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.

$$a+b=-12 ab=-220$$

Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -220.

$$1,-220 2,-110 4,-55 5,-44 10,-22 11,-20$$

Calculate the sum for each pair.

$$1-220=-219 2-110=-108 4-55=-51 5-44=-39 10-22=-12 11-20=-9$$

The solution is the pair that gives sum -12.

$$a=-22 b=10$$

Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.

$$\left(x-22\right)\left(x+10\right)$$

To find equation solutions, solve x-22=0 and x+10=0.

$$x=22 x=-10$$

Steps Using Factoring By Grouping

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-220. To find a and b, set up a system to be solved.

$$a+b=-12 ab=1\left(-220\right)=-220$$

Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -220.

$$1,-220 2,-110 4,-55 5,-44 10,-22 11,-20$$

Calculate the sum for each pair.

$$1-220=-219 2-110=-108 4-55=-51 5-44=-39 10-22=-12 11-20=-9$$

The solution is the pair that gives sum -12.

$$a=-22 b=10$$

Rewrite x^{2}-12x-220 as \left(x^{2}-22x\right)+\left(10x-220\right).

$$\left(x^{2}-22x\right)+\left(10x-220\right)$$

Factor out x in the first and 10 in the second group.

$$x\left(x-22\right)+10\left(x-22\right)$$

Factor out common term x-22 by using distributive property.

$$\left(x-22\right)\left(x+10\right)$$

To find equation solutions, solve x-22=0 and x+10=0.

$$x=22 x=-10$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x^{2}-12x-220=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -12 for b, and -220 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-12\right)±\sqrt{\left(-12\right)^{2}-4\left(-220\right)}}{2}$$

Square -12.

$$x=\frac{-\left(-12\right)±\sqrt{144-4\left(-220\right)}}{2}$$

Multiply -4 times -220.

$$x=\frac{-\left(-12\right)±\sqrt{144+880}}{2}$$

Add 144 to 880.

$$x=\frac{-\left(-12\right)±\sqrt{1024}}{2}$$

Take the square root of 1024.

$$x=\frac{-\left(-12\right)±32}{2}$$

The opposite of -12 is 12.

$$x=\frac{12±32}{2}$$

Now solve the equation x=\frac{12±32}{2} when ± is plus. Add 12 to 32.

$$x=\frac{44}{2}$$

Divide 44 by 2.

$$x=22$$

Now solve the equation x=\frac{12±32}{2} when ± is minus. Subtract 32 from 12.

$$x=-\frac{20}{2}$$

Divide -20 by 2.

$$x=-10$$

The equation is now solved.

$$x=22 x=-10$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$x^{2}-12x-220=0$$

Add 220 to both sides of the equation.

$$x^{2}-12x-220-\left(-220\right)=-\left(-220\right)$$

Subtracting -220 from itself leaves 0.

$$x^{2}-12x=-\left(-220\right)$$

Subtract -220 from 0.

$$x^{2}-12x=220$$

Divide -12, the coefficient of the x term, by 2 to get -6. Then add the square of -6 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-12x+\left(-6\right)^{2}=220+\left(-6\right)^{2}$$

Square -6.

$$x^{2}-12x+36=220+36$$

Add 220 to 36.

$$x^{2}-12x+36=256$$

Factor x^{2}-12x+36. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-6\right)^{2}=256$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-6\right)^{2}}=\sqrt{256}$$

Simplify.

$$x-6=16 x-6=-16$$

Add 6 to both sides of the equation.

$$x=22 x=-10$$