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x^{2}-115x+5046=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-115\right)±\sqrt{\left(-115\right)^{2}-4\times 5046}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -115 for b, and 5046 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-115\right)±\sqrt{13225-4\times 5046}}{2}
Square -115.
x=\frac{-\left(-115\right)±\sqrt{13225-20184}}{2}
Multiply -4 times 5046.
x=\frac{-\left(-115\right)±\sqrt{-6959}}{2}
Add 13225 to -20184.
x=\frac{-\left(-115\right)±\sqrt{6959}i}{2}
Take the square root of -6959.
x=\frac{115±\sqrt{6959}i}{2}
The opposite of -115 is 115.
x=\frac{115+\sqrt{6959}i}{2}
Now solve the equation x=\frac{115±\sqrt{6959}i}{2} when ± is plus. Add 115 to i\sqrt{6959}.
x=\frac{-\sqrt{6959}i+115}{2}
Now solve the equation x=\frac{115±\sqrt{6959}i}{2} when ± is minus. Subtract i\sqrt{6959} from 115.
x=\frac{115+\sqrt{6959}i}{2} x=\frac{-\sqrt{6959}i+115}{2}
The equation is now solved.
x^{2}-115x+5046=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-115x+5046-5046=-5046
Subtract 5046 from both sides of the equation.
x^{2}-115x=-5046
Subtracting 5046 from itself leaves 0.
x^{2}-115x+\left(-\frac{115}{2}\right)^{2}=-5046+\left(-\frac{115}{2}\right)^{2}
Divide -115, the coefficient of the x term, by 2 to get -\frac{115}{2}. Then add the square of -\frac{115}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-115x+\frac{13225}{4}=-5046+\frac{13225}{4}
Square -\frac{115}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-115x+\frac{13225}{4}=-\frac{6959}{4}
Add -5046 to \frac{13225}{4}.
\left(x-\frac{115}{2}\right)^{2}=-\frac{6959}{4}
Factor x^{2}-115x+\frac{13225}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{115}{2}\right)^{2}}=\sqrt{-\frac{6959}{4}}
Take the square root of both sides of the equation.
x-\frac{115}{2}=\frac{\sqrt{6959}i}{2} x-\frac{115}{2}=-\frac{\sqrt{6959}i}{2}
Simplify.
x=\frac{115+\sqrt{6959}i}{2} x=\frac{-\sqrt{6959}i+115}{2}
Add \frac{115}{2} to both sides of the equation.