Solve x^2-10+18=0

$${ x }^{ 2 } -10+18=0$$

Solve for x (complex solution)

$$x=-2\sqrt{2}i\approx -0-2.828427125i$$

$$x=2\sqrt{2}i\approx 2.828427125i$$

Steps by Finding Square Root

Add -10 and 18 to get 8.

$$x^{2}+8=0$$

Subtract 8 from both sides. Anything subtracted from zero gives its negation.

$$x^{2}=-8$$

The equation is now solved.

$$x=2\sqrt{2}i x=-2\sqrt{2}i$$

Steps Using the Quadratic Formula

Add -10 and 18 to get 8.

$$x^{2}+8=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 8}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 8}}{2}$$

Multiply -4 times 8.

$$x=\frac{0±\sqrt{-32}}{2}$$

Take the square root of -32.

$$x=\frac{0±4\sqrt{2}i}{2}$$

Now solve the equation x=\frac{0±4\sqrt{2}i}{2} when ± is plus.

$$x=2\sqrt{2}i$$

Now solve the equation x=\frac{0±4\sqrt{2}i}{2} when ± is minus.

$$x=-2\sqrt{2}i$$

The equation is now solved.

$$x=2\sqrt{2}i x=-2\sqrt{2}i$$