Solve x^2-3^6=1

$${ x }^{ 2 } - { 3 }^{ 6 } =1$$

Solve for x

$$x=\sqrt{730}\approx 27.018512172$$

$$x=-\sqrt{730}\approx -27.018512172$$

Steps by Finding Square Root

Calculate 3 to the power of 6 and get 729.

$$x^{2}-729=1$$

Add 729 to both sides.

$$x^{2}=1+729$$

Add 1 and 729 to get 730.

$$x^{2}=730$$

Take the square root of both sides of the equation.

$$x=\sqrt{730} x=-\sqrt{730}$$

Steps Using the Quadratic Formula

Calculate 3 to the power of 6 and get 729.

$$x^{2}-729=1$$

Subtract 1 from both sides.

$$x^{2}-729-1=0$$

Subtract 1 from -729 to get -730.

$$x^{2}-730=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -730 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-730\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-730\right)}}{2}$$

Multiply -4 times -730.

$$x=\frac{0±\sqrt{2920}}{2}$$

Take the square root of 2920.

$$x=\frac{0±2\sqrt{730}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{730}}{2} when ± is plus.

$$x=\sqrt{730}$$

Now solve the equation x=\frac{0±2\sqrt{730}}{2} when ± is minus.

$$x=-\sqrt{730}$$

The equation is now solved.

$$x=\sqrt{730} x=-\sqrt{730}$$