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x^{2}-\left(x^{2}-4x+4\right)=4^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
x^{2}-x^{2}+4x-4=4^{2}
To find the opposite of x^{2}-4x+4, find the opposite of each term.
4x-4=4^{2}
Combine x^{2} and -x^{2} to get 0.
4x-4=16
Calculate 4 to the power of 2 and get 16.
4x=16+4
Add 4 to both sides.
4x=20
Add 16 and 4 to get 20.
x=\frac{20}{4}
Divide both sides by 4.
x=5
Divide 20 by 4 to get 5.