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x^{2}-\left(16-8x+x^{2}\right)=3^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4-x\right)^{2}.
x^{2}-16+8x-x^{2}=3^{2}
To find the opposite of 16-8x+x^{2}, find the opposite of each term.
-16+8x=3^{2}
Combine x^{2} and -x^{2} to get 0.
-16+8x=9
Calculate 3 to the power of 2 and get 9.
8x=9+16
Add 16 to both sides.
8x=25
Add 9 and 16 to get 25.
x=\frac{25}{8}
Divide both sides by 8.