Solve for x
x = \frac{109}{20} = 5\frac{9}{20} = 5.45
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x^{2}=9+100-20x+x^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(10-x\right)^{2}.
x^{2}=109-20x+x^{2}
Add 9 and 100 to get 109.
x^{2}+20x=109+x^{2}
Add 20x to both sides.
x^{2}+20x-x^{2}=109
Subtract x^{2} from both sides.
20x=109
Combine x^{2} and -x^{2} to get 0.
x=\frac{109}{20}
Divide both sides by 20.
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