Solve x^2=400+left(60-xright)^2

$${ x }^{ 2 } =400+ { \left(60-x \right) }^{ 2 }$$

Solve for x

$$x = \frac{100}{3} = 33\frac{1}{3} \approx 33.333333333$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(60-x\right)^{2}.

$$x^{2}=400+3600-120x+x^{2}$$

Add 400 and 3600 to get 4000.

$$x^{2}=4000-120x+x^{2}$$

Add 120x to both sides.

$$x^{2}+120x=4000+x^{2}$$

Subtract x^{2} from both sides.

$$x^{2}+120x-x^{2}=4000$$

Combine x^{2} and -x^{2} to get 0.

$$120x=4000$$

Divide both sides by 120.

$$x=\frac{4000}{120}$$

Reduce the fraction \frac{4000}{120} to lowest terms by extracting and canceling out 40.

$$x=\frac{100}{3}$$