Solve x^2=2655^

$${ x }^{ 2 } = { 2655 }^{ }$$

Solve for x

$$x=3\sqrt{295}\approx 51.526692112$$

$$x=-3\sqrt{295}\approx -51.526692112$$

Steps by Finding Square Root

Calculate 2655 to the power of 1 and get 2655.

$$x^{2}=2655$$

Take the square root of both sides of the equation.

$$x=3\sqrt{295} x=-3\sqrt{295}$$

Steps Using the Quadratic Formula

Calculate 2655 to the power of 1 and get 2655.

$$x^{2}=2655$$

Subtract 2655 from both sides.

$$x^{2}-2655=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -2655 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2655\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-2655\right)}}{2}$$

Multiply -4 times -2655.

$$x=\frac{0±\sqrt{10620}}{2}$$

Take the square root of 10620.

$$x=\frac{0±6\sqrt{295}}{2}$$

Now solve the equation x=\frac{0±6\sqrt{295}}{2} when ± is plus.

$$x=3\sqrt{295}$$

Now solve the equation x=\frac{0±6\sqrt{295}}{2} when ± is minus.

$$x=-3\sqrt{295}$$

The equation is now solved.

$$x=3\sqrt{295} x=-3\sqrt{295}$$