Solve x^2=sqrt{963^2}

$${ x }^{ 2 } = \sqrt{ { 963 }^{ 2 } }$$

Solve for x

$$x=3\sqrt{107}\approx 31.032241298$$

$$x=-3\sqrt{107}\approx -31.032241298$$

Steps by Finding Square Root

Calculate 963 to the power of 2 and get 927369.

$$x^{2}=\sqrt{927369}$$

Calculate the square root of 927369 and get 963.

$$x^{2}=963$$

Take the square root of both sides of the equation.

$$x=3\sqrt{107} x=-3\sqrt{107}$$

Steps Using the Quadratic Formula

Calculate 963 to the power of 2 and get 927369.

$$x^{2}=\sqrt{927369}$$

Calculate the square root of 927369 and get 963.

$$x^{2}=963$$

Subtract 963 from both sides.

$$x^{2}-963=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -963 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-963\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-963\right)}}{2}$$

Multiply -4 times -963.

$$x=\frac{0±\sqrt{3852}}{2}$$

Take the square root of 3852.

$$x=\frac{0±6\sqrt{107}}{2}$$

Now solve the equation x=\frac{0±6\sqrt{107}}{2} when ± is plus.

$$x=3\sqrt{107}$$

Now solve the equation x=\frac{0±6\sqrt{107}}{2} when ± is minus.

$$x=-3\sqrt{107}$$

The equation is now solved.

$$x=3\sqrt{107} x=-3\sqrt{107}$$