Solve x^2=pi

$${ x }^{ 2 } = \pi$$

Solve for x

$$x=\sqrt{\pi }\approx 1.772453851$$

$$x=-\sqrt{\pi }\approx -1.772453851$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x=\sqrt{\pi } x=-\sqrt{\pi }$$

Steps Using the Quadratic Formula

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$x^{2}=\pi$$

Subtract \pi from both sides of the equation.

$$x^{2}-\pi =\pi -\pi$$

Subtracting \pi from itself leaves 0.

$$x^{2}-\pi =0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\pi for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\pi \right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-\pi \right)}}{2}$$

Multiply -4 times -\pi .

$$x=\frac{0±\sqrt{4\pi }}{2}$$

Take the square root of 4\pi .

$$x=\frac{0±2\sqrt{\pi }}{2}$$

Now solve the equation x=\frac{0±2\sqrt{\pi }}{2} when ± is plus.

$$x=\sqrt{\pi }$$

Now solve the equation x=\frac{0±2\sqrt{\pi }}{2} when ± is minus.

$$x=-\sqrt{\pi }$$

The equation is now solved.

$$x=\sqrt{\pi } x=-\sqrt{\pi }$$