Solve x^2+x+6=-x^2-3x+left(-2+2x^2right)

$${ x }^{ 2 } +x+6 = - { x }^{ 2 } -3x+ \left( -2+2 { x }^{ 2 } \right)$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Add x^{2} to both sides.

$$x^{2}+x+6+x^{2}=-3x-2+2x^{2}$$

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}+x+6=-3x-2+2x^{2}$$

Add 3x to both sides.

$$2x^{2}+x+6+3x=-2+2x^{2}$$

Combine x and 3x to get 4x.

$$2x^{2}+4x+6=-2+2x^{2}$$

Subtract 2x^{2} from both sides.

$$2x^{2}+4x+6-2x^{2}=-2$$

Combine 2x^{2} and -2x^{2} to get 0.

$$4x+6=-2$$

Subtract 6 from both sides.

$$4x=-2-6$$

Subtract 6 from -2 to get -8.

$$4x=-8$$

Divide both sides by 4.

$$x=\frac{-8}{4}$$

Divide -8 by 4 to get -2.

$$x=-2$$