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x^{2}+9x-14=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-9±\sqrt{9^{2}-4\left(-14\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-9±\sqrt{81-4\left(-14\right)}}{2}
Square 9.
x=\frac{-9±\sqrt{81+56}}{2}
Multiply -4 times -14.
x=\frac{-9±\sqrt{137}}{2}
Add 81 to 56.
x=\frac{\sqrt{137}-9}{2}
Now solve the equation x=\frac{-9±\sqrt{137}}{2} when ± is plus. Add -9 to \sqrt{137}.
x=\frac{-\sqrt{137}-9}{2}
Now solve the equation x=\frac{-9±\sqrt{137}}{2} when ± is minus. Subtract \sqrt{137} from -9.
x^{2}+9x-14=\left(x-\frac{\sqrt{137}-9}{2}\right)\left(x-\frac{-\sqrt{137}-9}{2}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{-9+\sqrt{137}}{2} for x_{1} and \frac{-9-\sqrt{137}}{2} for x_{2}.