Solve x^2+8x+7=125542

$${ x }^{ 2 } +8x+7=125542$$

Solve for x (complex solution)

$$x=\sqrt{125551}-4\approx 350.33176544$$

$$x=-\left(\sqrt{125551}+4\right)\approx -358.33176544$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x^{2}+8x+7=125542$$

Subtract 125542 from both sides of the equation.

$$x^{2}+8x+7-125542=125542-125542$$

Subtracting 125542 from itself leaves 0.

$$x^{2}+8x+7-125542=0$$

Subtract 125542 from 7.

$$x^{2}+8x-125535=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 8 for b, and -125535 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-8±\sqrt{8^{2}-4\left(-125535\right)}}{2}$$

Square 8.

$$x=\frac{-8±\sqrt{64-4\left(-125535\right)}}{2}$$

Multiply -4 times -125535.

$$x=\frac{-8±\sqrt{64+502140}}{2}$$

Add 64 to 502140.

$$x=\frac{-8±\sqrt{502204}}{2}$$

Take the square root of 502204.

$$x=\frac{-8±2\sqrt{125551}}{2}$$

Now solve the equation x=\frac{-8±2\sqrt{125551}}{2} when ± is plus. Add -8 to 2\sqrt{125551}.

$$x=\frac{2\sqrt{125551}-8}{2}$$

Divide -8+2\sqrt{125551} by 2.

$$x=\sqrt{125551}-4$$

Now solve the equation x=\frac{-8±2\sqrt{125551}}{2} when ± is minus. Subtract 2\sqrt{125551} from -8.

$$x=\frac{-2\sqrt{125551}-8}{2}$$

Divide -8-2\sqrt{125551} by 2.

$$x=-\sqrt{125551}-4$$

The equation is now solved.

$$x=\sqrt{125551}-4 x=-\sqrt{125551}-4$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$x^{2}+8x+7=125542$$

Subtract 7 from both sides of the equation.

$$x^{2}+8x+7-7=125542-7$$

Subtracting 7 from itself leaves 0.

$$x^{2}+8x=125542-7$$

Subtract 7 from 125542.

$$x^{2}+8x=125535$$

Divide 8, the coefficient of the x term, by 2 to get 4. Then add the square of 4 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+8x+4^{2}=125535+4^{2}$$

Square 4.

$$x^{2}+8x+16=125535+16$$

Add 125535 to 16.

$$x^{2}+8x+16=125551$$

Factor x^{2}+8x+16. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+4\right)^{2}=125551$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+4\right)^{2}}=\sqrt{125551}$$

Simplify.

$$x+4=\sqrt{125551} x+4=-\sqrt{125551}$$

Subtract 4 from both sides of the equation.

$$x=\sqrt{125551}-4 x=-\sqrt{125551}-4$$

Solve for x

$$x=\sqrt{125551}-4\approx 350.33176544$$

$$x=-\sqrt{125551}-4\approx -358.33176544$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x^{2}+8x+7=125542$$

Subtract 125542 from both sides of the equation.

$$x^{2}+8x+7-125542=125542-125542$$

Subtracting 125542 from itself leaves 0.

$$x^{2}+8x+7-125542=0$$

Subtract 125542 from 7.

$$x^{2}+8x-125535=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 8 for b, and -125535 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-8±\sqrt{8^{2}-4\left(-125535\right)}}{2}$$

Square 8.

$$x=\frac{-8±\sqrt{64-4\left(-125535\right)}}{2}$$

Multiply -4 times -125535.

$$x=\frac{-8±\sqrt{64+502140}}{2}$$

Add 64 to 502140.

$$x=\frac{-8±\sqrt{502204}}{2}$$

Take the square root of 502204.

$$x=\frac{-8±2\sqrt{125551}}{2}$$

Now solve the equation x=\frac{-8±2\sqrt{125551}}{2} when ± is plus. Add -8 to 2\sqrt{125551}.

$$x=\frac{2\sqrt{125551}-8}{2}$$

Divide -8+2\sqrt{125551} by 2.

$$x=\sqrt{125551}-4$$

Now solve the equation x=\frac{-8±2\sqrt{125551}}{2} when ± is minus. Subtract 2\sqrt{125551} from -8.

$$x=\frac{-2\sqrt{125551}-8}{2}$$

Divide -8-2\sqrt{125551} by 2.

$$x=-\sqrt{125551}-4$$

The equation is now solved.

$$x=\sqrt{125551}-4 x=-\sqrt{125551}-4$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$x^{2}+8x+7=125542$$

Subtract 7 from both sides of the equation.

$$x^{2}+8x+7-7=125542-7$$

Subtracting 7 from itself leaves 0.

$$x^{2}+8x=125542-7$$

Subtract 7 from 125542.

$$x^{2}+8x=125535$$

Divide 8, the coefficient of the x term, by 2 to get 4. Then add the square of 4 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+8x+4^{2}=125535+4^{2}$$

Square 4.

$$x^{2}+8x+16=125535+16$$

Add 125535 to 16.

$$x^{2}+8x+16=125551$$

Factor x^{2}+8x+16. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+4\right)^{2}=125551$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+4\right)^{2}}=\sqrt{125551}$$

Simplify.

$$x+4=\sqrt{125551} x+4=-\sqrt{125551}$$

Subtract 4 from both sides of the equation.

$$x=\sqrt{125551}-4 x=-\sqrt{125551}-4$$