Solve x^2+8x+6=

$${ x }^{ 2 } +8x+6=$$

Factor

$$\left(x-\left(-\sqrt{10}-4\right)\right)\left(x-\left(\sqrt{10}-4\right)\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$x^{2}+8x+6=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-8±\sqrt{8^{2}-4\times 6}}{2}$$

Square 8.

$$x=\frac{-8±\sqrt{64-4\times 6}}{2}$$

Multiply -4 times 6.

$$x=\frac{-8±\sqrt{64-24}}{2}$$

Add 64 to -24.

$$x=\frac{-8±\sqrt{40}}{2}$$

Take the square root of 40.

$$x=\frac{-8±2\sqrt{10}}{2}$$

Now solve the equation x=\frac{-8±2\sqrt{10}}{2} when ± is plus. Add -8 to 2\sqrt{10}.

$$x=\frac{2\sqrt{10}-8}{2}$$

Divide -8+2\sqrt{10} by 2.

$$x=\sqrt{10}-4$$

Now solve the equation x=\frac{-8±2\sqrt{10}}{2} when ± is minus. Subtract 2\sqrt{10} from -8.

$$x=\frac{-2\sqrt{10}-8}{2}$$

Divide -8-2\sqrt{10} by 2.

$$x=-\sqrt{10}-4$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -4+\sqrt{10} for x_{1} and -4-\sqrt{10} for x_{2}.

$$x^{2}+8x+6=\left(x-\left(\sqrt{10}-4\right)\right)\left(x-\left(-\sqrt{10}-4\right)\right)$$

Evaluate

$$x^{2}+8x+6$$